3c^2-19c=14

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Solution for 3c^2-19c=14 equation:


Simplifying
3c2 + -19c = 14

Reorder the terms:
-19c + 3c2 = 14

Solving
-19c + 3c2 = 14

Solving for variable 'c'.

Reorder the terms:
-14 + -19c + 3c2 = 14 + -14

Combine like terms: 14 + -14 = 0
-14 + -19c + 3c2 = 0

Factor a trinomial.
(-2 + -3c)(7 + -1c) = 0

Subproblem 1

Set the factor '(-2 + -3c)' equal to zero and attempt to solve: Simplifying -2 + -3c = 0 Solving -2 + -3c = 0 Move all terms containing c to the left, all other terms to the right. Add '2' to each side of the equation. -2 + 2 + -3c = 0 + 2 Combine like terms: -2 + 2 = 0 0 + -3c = 0 + 2 -3c = 0 + 2 Combine like terms: 0 + 2 = 2 -3c = 2 Divide each side by '-3'. c = -0.6666666667 Simplifying c = -0.6666666667

Subproblem 2

Set the factor '(7 + -1c)' equal to zero and attempt to solve: Simplifying 7 + -1c = 0 Solving 7 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '-7' to each side of the equation. 7 + -7 + -1c = 0 + -7 Combine like terms: 7 + -7 = 0 0 + -1c = 0 + -7 -1c = 0 + -7 Combine like terms: 0 + -7 = -7 -1c = -7 Divide each side by '-1'. c = 7 Simplifying c = 7

Solution

c = {-0.6666666667, 7}

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